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9x^2-48x+15=0
a = 9; b = -48; c = +15;
Δ = b2-4ac
Δ = -482-4·9·15
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-42}{2*9}=\frac{6}{18} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+42}{2*9}=\frac{90}{18} =5 $
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